Wednesday

August 27, 2014

August 27, 2014

Posted by **Emily** on Thursday, September 13, 2007 at 9:58am.

Mr. Jackson is preparing bags of treats to give trick or treaters. He has 48 pieces of candy and 60 pieces of gum. He uses all the candy and gum, and he puts the same ratio of candy to gum in each bag. What is the largest number of bags he could have made?

Yes, the answer would be great, but I love math and am trying to figure out what method I should use to figure this out.

Thank you,

Emily

PS: i may be back now that I found you!

- Math -
**bobpursley**, Thursday, September 13, 2007 at 10:06amWhat factors divides both numbers evenly? For instance 2,

Each of two bags has 30gum, and 24 candies.

Maybe the common factor needs to be larger.

- Math -
**Emily**, Thursday, September 13, 2007 at 10:43am'k .. I think my brain is not working .. I don't think other 8 year olds have to do this .. My mother is creating a short circuit. I am confused. I should have gone higher to 12. Thank you for that tip. So would the answer be 4 bags since gum would be too many or would it be 5 bags ... Okay,now that I am thinking, I think 5 bags because I see it says ALL CANDY AND GUM ARE USED, so it must be the higher number. Please tell me I am right and if not then tell my mom this is too hard. She thinks I can do it but I think she thinks too much! lol! Again, thank you for your help! emily

- Math -
- Math -
**Emily**, Thursday, September 13, 2007 at 10:21amThank you very much. I think I got it. Can you tell me if the answer would be 8 with 2 gums left over? If not I will try again. My mom by the way is laughing. She didn't think I could find help so quickly! lol ..Thanks for helping me.

Emily

- Math -
**bobpursley**, Thursday, September 13, 2007 at 10:27amto get 8 candies, the divisor is six, which goes into 60 evenly, so no gums will be left over.

I wonder if 12 goes into each evenly?

- Math -
**Emily**, Thursday, September 13, 2007 at 10:35amOkay I will try again. I was thinking that 6 was the largest number and since the question said what would be the largest number of bags I thought 8 because 6 goes into 48, 8 times and into 60 10 times, which would be 8 bags possible to make, keeping the bags even, leaving you 2 pieces of gum leftover .... but I will try again ... :-( .. thank you. Emily.

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