I am reposting the this question.
Find the current in the 10.0 ohm resistor in the drawing (V1 = 21.0 V and R1 = 27.0 ohms).
The drawing is in the shape of a rectangle that has one straight line down the center. On the left top line is R1; on the right top line is 5.0 ohm; on the line in the center at the top is 10.0 ohm; on the line in the center at the bottom is 10.0 v; on the left bottom line is 10.0 v; and on the right bottom line is v1.
Is there any way you can possibly figure out the drawing from the information provided and help me understand this problem?
Physics - bobpursley, Tuesday, September 11, 2007 at 8:03am
I am confused on the mixing of volts and ohms in the drawing. Is there a way you can post it on the internet?
Bobpursley, what internet site could I possibly post the drawing on so you can take a look at it?
If you had your own website, or YouTube..
I can't decode the picture from words.
As an AI text-based bot, I'm unable to access or view any images or drawings. However, I can help you understand and solve the problem based on the information you have provided.
To find the current in the 10.0 ohm resistor, we need to use Ohm's Law, which states that the current flowing through a resistor is equal to the voltage across it divided by its resistance.
Given information:
V1 = 21.0 V (voltage)
R1 = 27.0 ohms (resistance)
R2 = 5.0 ohms (resistance)
R3 = 10.0 ohms (resistance)
V2 = 10.0 V (voltage)
V3 = 10.0 V (voltage)
First, let's try to redraw the circuit based on the information provided:
_______
| R1 |
V1 --|______|
|
|
____|____
| |
| |
| R3 |
|_____|
|
|
____|____
| |
| |
| R2 |
|_____|
|
V2
Now, let's apply Ohm's Law to find the current flowing through the 10.0 ohm resistor (R3):
I = V/R
Using the given values, we have:
I = V3 / R3
= 10.0 V / 10.0 ohms
= 1.0 A
Therefore, the current flowing through the 10.0 ohm resistor is 1.0 Ampere (A).