Posted by **manny** on Tuesday, September 11, 2007 at 10:08pm.

Find the distance from point P<5,5,2> to the line x=0 , y=5-5t, z=2+t.

I keep getting 0 and that's not the correct answer and I can't figure out what's going wrong.

- Calculus -
**drwls**, Wednesday, September 12, 2007 at 2:09am
Expressed in terms of the paratmer t, the squared distance from P to any point on the line is

D^2 = (x1-x2)^2 + (y1-y2)^2 +(z1-z2)^2

=5^2 + (5-5t-5)^2 + (2+t-2)^2

= 25 + 25t^2 + t^2 = 26 t^2 + 25

Differentiate with respect to t and set the derivative equal to zero to find where the distance is a minimum

52t = 0

t = 0

At that value of t, the distance^2 is

D^2 = 25

so D = 5

## Answer This Question

## Related Questions

- alg. - Find the slope of the line passing through the points (–2, 1) and (3, 9...
- Geometry - Okay, this is a problem that I've tried over ten times before getting...
- Algebra - Find an equation of the line having the given slope and containing the...
- calculus - For x>0 find and simplify the derivative of f(x)= arctan(x) + ...
- calculus - please help! Find an equation of the tangent line to the curve at the...
- Chemistry - One other question that I cannot figure out what I'm doing wrong is ...
- Statistics check - Complete the hypothesis test with alternative hypothesis ƒÊd...
- Calculus - Find the volume of the solid obtained by rotating the region bounded ...
- Physics - a ball is dropped from the top on an 80-m high building. what speed ...
- Calculus - Compute (f^-1) (2) if f(x) = 7x + 3cos(x) + 2sin(x).... We tried ...

More Related Questions