Thursday

March 5, 2015

March 5, 2015

Posted by **manny** on Tuesday, September 11, 2007 at 10:08pm.

I keep getting 0 and that's not the correct answer and I can't figure out what's going wrong.

- Calculus -
**drwls**, Wednesday, September 12, 2007 at 2:09amExpressed in terms of the paratmer t, the squared distance from P to any point on the line is

D^2 = (x1-x2)^2 + (y1-y2)^2 +(z1-z2)^2

=5^2 + (5-5t-5)^2 + (2+t-2)^2

= 25 + 25t^2 + t^2 = 26 t^2 + 25

Differentiate with respect to t and set the derivative equal to zero to find where the distance is a minimum

52t = 0

t = 0

At that value of t, the distance^2 is

D^2 = 25

so D = 5

**Answer this Question**

**Related Questions**

Geometry - Okay, this is a problem that I've tried over ten times before getting...

Algebra - Find an equation of the line having the given slope and containing the...

precalc - I;m not sure if i am doing this right...I keep getting a negative ...

Calculus I - Hi, I'm trying to figure this out, but the answer I keep coming up ...

calculus - For x>0 find and simplify the derivative of f(x)= arctan(x) + ...

calculus - Consider line segments which are tangent to a point on the right half...

math - Find the exact value of the shortest distance from the origin to each ...

Statistics check - Complete the hypothesis test with alternative hypothesis ƒÊd...

algebra - I don't know proceedure to figure, I have answer: -50 I cannot figue ...

Maths - Optimisation - I've been trying to work out this question for hours and ...