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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Tuesday, September 11, 2007 at 9:04pm.

If you ride a bicycle a distance of 5 miles in 15 minutes at a constant speed and if the bicycle's wheels have diameter 27 in., find the wheels approximate rate of turn (in revoultions per minute)

Can someone at least help me get started even if you cannot answer the question completely. Thanks

- Honors Pre-Calculus -
**bobpursley**, Tuesday, September 11, 2007 at 9:21pmTHe wheel has to cover 5 miles, right? So divide the 5miles by the wheel circumference to get the number of turns, and then divide by time.

- Honors Pre-Calculus -
**Anonymous**, Tuesday, September 11, 2007 at 9:54pmCan you or someone else please clarify your explanation. Thank you.

- Honors Pre-Calculus -
- Honors Pre-Calculus -
**Ms. Sue**, Tuesday, September 11, 2007 at 10:01pmWhat part of Mr. Pursley's explanation don't you understand? He's given you these steps:

Divide the 5 miles by the wheel circumference. That gives you the number of turns.

Divide the number of turns by the time.

- Honors Pre-Calculus -
**Anonymous**, Tuesday, September 11, 2007 at 10:06pmI understand what he's telling me to do, but I've gone through it multiple times and it just doesn't seem correct.

- Honors Pre-Calculus -
**Ms. Sue**, Tuesday, September 11, 2007 at 10:08pmWhat answer did you get?

- Honors Pre-Calculus -
**Anonymous**, Tuesday, September 11, 2007 at 10:12pmIf I understand the steps correctly, 27x 3.14= 84.78 divided by 5= 16.956 divided by 15= 1.1304 (which seems pretty slow) If you notice a mistake I have made in the procedure please let me know. Thanks

- Honors Pre-Calculus -

- Honors Pre-Calculus -

- Honors Pre-Calculus -
- Honors Pre-Calculus -
**bobpursley**, Tuesday, September 11, 2007 at 10:17pmnumber of turns=5miles/(27inches*PI)

Now, you have to convert miles to inches to divide this out.

Then, after you get revolutions from the above, divide by 15 min to get rev/min

- Honors Pre-Calculus -
**Anonymous**, Tuesday, September 11, 2007 at 10:20pmThank you I appreciate all the help.

- Honors Pre-Calculus -

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