Homework Help: physicsss

Posted by confusedd!HELPP!!! on Tuesday, September 11, 2007 at 8:15pm.

while driving his sports car at 20.0 m/s down a four-lane highway, eddie comes up behind a slow-moving dump truck and decides to pass it in the left lane. If eddie can accelerate at 5.00 m/s2) (squared) how long will it take for him to reach a speed of 30.0 m/s?

i know its

Vfinal=Vinitial+acceleration*time but i dont know what 5.00 m/s2 (squared) means...
would it be 30.0 = 20.0 + 5.00 m/s^2 (squared) * time, but i have to solve for time..... whats the squared for....? can you write me this equation in numbers so i can just slove it, because i know how it goes just the squared confuses me....

physicsss - drwls, Tuesday, September 11, 2007 at 8:58pm
5.00 m/s^2 is the acceleration rate of the passing car. Multiply it by the time interval for the velocity change/ You havew already written the correct equation. Solve if for t.

t = (10 m/s)/(5 m/s^2)

Your answer will be in seconds
physicsss - drwls, Tuesday, September 11, 2007 at 9:00pm
5.00 m/s^2 is the acceleration rate of the passing car. Multiply it by the time interval for the velocity change/ You havew already written the correct equation. Solve if for t.

t = (10 m/s)/(5 m/s^2)

Your answer will be in seconds

Answer this Question

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