In an experiment, a student measures the speed of sound in air to be 318 m/s at STP. If the accepted value for the speed of sound under those conditionsis 331 m/s, what is the student's percent error?
a. 3.9% b. 3.93% c. 4.09% d. 4.1%
I tried but it didn't work. This is wat I did:331-318=-13x100=-1300
See my answer below at your original post.
To calculate percent error, you need to determine the difference between the experimental value and the accepted value, and then divide that difference by the accepted value. Finally, multiply the result by 100 to get the percentage.
In this case, the accepted value is 331 m/s, and the student measured a value of 318 m/s. Therefore, the difference between the experimental and accepted value is 331 - 318 = -13 m/s.
To find the percent error, you need to divide this difference (-13) by the accepted value (331), and then multiply by 100:
Percent error = (-13 / 331) * 100
Calculating this expression will give you the correct answer.