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physics

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Hi: We have a homework problem that I have no idea even how to set up! please help!

"A man jogs at a speed of 1.3 m/s. His dog waits 1.4s then takes off running at a speed of 2.8 m/s to catch the man. How far will they have to travel before the dog watches up with the man? Answerin units of m"

  • physics - ,

    rate of man = 1.3 m/s
    t+1.4 s = time man jogs.
    distance covered by man is distance = rate x time = 1.3(t+1.4)

    rate of dog = 2.8 m/s.
    t = time dog runs.
    distance covered by dog is distance = rate x time = 2.8t

    Both run the same distance so set distance = rate x time equal to each other. That is
    distance man runs = distance dog runs. Check my thinking. Check my work. I found a little over 3 meters. Post your work if you get stuck.

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