Posted by Ty on Tuesday, September 11, 2007 at 4:20pm.
rate of man = 1.3 m/s
t+1.4 s = time man jogs.
distance covered by man is distance = rate x time = 1.3(t+1.4)
rate of dog = 2.8 m/s.
t = time dog runs.
distance covered by dog is distance = rate x time = 2.8t
Both run the same distance so set distance = rate x time equal to each other. That is
distance man runs = distance dog runs. Check my thinking. Check my work. I found a little over 3 meters. Post your work if you get stuck.
Related Questions
physics - Hi: We have a homework problem that I have no idea even how to set up...
Physics - A man jogs at a speed of 1.7 m/s. His dog waits 2.5 s and then takes o...
physics - This is a sample question: A man jogs at a speed of 1.2 m/s. His dog ...
physics - Okay, I have an example problem that I'm trying to solve that ...
physics - A man jogs at a speed of 1.7 m/s. His dog waits 1.9 s and then takes ...
physics - A man jogs at a speed of 1.7 m/s. His dog waits 1.4 s and then takes ...
physics - A man jogs at a spee of 1.1 m/s. His dog waits 1.6s and then takes off...
Physics - Man jogs 1.5 m/s. Dog waits 1.8 s then runs at 3.7 m/s. How far will ...
physics - The figure below shows the speed of a person's body as he does a ...
Chem (but i think its physics) - Ok so this problem appeared in my online chem ...
For Further Reading
