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September 21, 2014

September 21, 2014

Posted by **Tammy** on Tuesday, September 11, 2007 at 3:25pm.

a) what is the final speed of the car?

b) how far does the car travel?

a) v = v_0 +at

=0+2(3)= 6m/s

Would I use the part of the question where the car decelerates to 2 m/s for 3 s? Or would t=10s and a=2m/s^s?

b) d= 1/2at^2

=1/2 (6)(10)^2

=1/2(600)

=300m

I got 6m/s^2 as the acceleration from question a)

Is this correct?

- Physics -
**bobpursley**, Tuesday, September 11, 2007 at 3:34pma) find the first acceleration:

vf=vo+at= 5*4= 20m/s, then it slows

vf=20m/s-2*3= 14m/s

how far: break it up into three parts again, and solve.

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