Posted by **Tammy** on Tuesday, September 11, 2007 at 3:13pm.

A car starts from rest and undergoes uniform acceleration. During the first second it travels 6 m.

a) what is the car's acceleration?

b) How far will the car travel during the third second?

For a) I used v= v_0 +at

6=0 a*1 so a= 6m/s^2

For b) I used d=d_0 +v_0t + 1/2 at^2

=0 +0(3) + 1/2 (6)(3)^2

= 1/2(6)(9)

=27 m

Did I work out this problem correctly? Thanks in advance for your help.

- Physics -
**bobpursley**, Tuesday, September 11, 2007 at 3:35pm
a is right.

b, find how far it went in two seconds, then in three seconds, and subtract to find how far in the third second.

## Answer this Question

## Related Questions

- Physics - A car starts from rest and undergoes uniform acceleration. During the ...
- Physics - 7. A formula 1 racecar is capable of very quick starts (with a launch...
- physics - 2 cars are in a race the first car is 200m ahead of the second car.the...
- physics - A car starts from rest and travels for t1 seconds with a uniform ...
- physics - Starting from rest a car undergoes a constant acceleration of 6 m/s2. ...
- Physics - A car starts from rest and travels for 5.9 s with a uniform ...
- physics - A car starts from rest and travels for 5.3 s with a uniform ...
- physics - A car starts from rest and travels for 5.3 s with a uniform ...
- physics - A car starts from rest and travels for 6.0 s with a uniform ...
- Physics - A car starts from rest and travels for 5.4 s with a uniform ...