Saturday

April 19, 2014

April 19, 2014

Posted by **kelly** on Tuesday, September 11, 2007 at 1:53pm.

Part a -

O is the centre of the circle, and P , Q are points on the

circumference of the circle, with the angle POQ being a right angle. The radius of the circle is 3 cm.

Choose the option that is the area of the smaller sector POQ, correct to 3 decimal places.

Options - A) 7.065 cm^2 B) 7.069 cm^2 C) 7.071 cm^2

D) 10.07 cm^2

Part b-

Choose the option that is the perimeter of the smaller sector POQ, correct to 3 significant figures. (The perimeter of the sector is the distance around all the edges of the sector.)

Options - A) 7.069 cm B) 7.07 cm C) 10.7 cm D) 10.712 cm

for part a i thinks its 7.069cm squred

but i dont knw what part b is

- maths -
**Ms. Sue**, Tuesday, September 11, 2007 at 2:21pmI got a different answer for Part a. I first figured the area of the complete circle [A = pi(r^2)]. Then I found one fourth of the complete area.

For Part b, you first need the total circumference of the circle. Using the formula C = pi (2r), I get 18.8496 cm. One "side" of the sector then is 18.84/4 = 4.7124.

Add 4.7124 to the other two sides of the sector to find the total perimeter.

**Related Questions**

maths - 1) Circle centre (7,-2) passes through (-2,10). Calculate radius and ...

math - can u help this the qustion is : A circle passes through the points (1,4...

steev - can u help this the qustion is : A circle passes through the points (1,4...

maths-Circles - O is the centre of a circle which has two chords BA and BC with ...

Maths Help - A,B,C,D,E,F are 6 consecutive points on the circumference of a ...

maths - O is the centre of the circle and A and B are points on the ...

math - The equation of a circle with centre O(0,0) is x^2+y^2=40. The points A(-...

maths - Given that the equation of the circle is x^2+y^2+2x-8y+5=0 (i)find the ...

maths - Given that the equation of the circle is x^2 + y^2 +2x -8y+5 =0 (i)Find ...

Gradient of circle? - A circle has the equation x^2+y^2-4x+6y-12=0 and i have ...