virginia threw a frisbee for a distance of 138.56m to capture the womans recrod. If the frisbee was thrown horizontally with a speed of 13.0 m/s, how long did the frisbee remain aloft?
(time interval) = (distance)/(speed)
Do the division.
Express the answer wiih three significant figures.
To find out how long the frisbee remained aloft, we can use the equation of motion:
distance = initial velocity × time
In this case, since the frisbee was thrown horizontally, the initial vertical velocity is 0 m/s. So, the equation simplifies to:
distance = horizontal velocity × time
Rearranging the equation, we can solve for time:
time = distance / horizontal velocity
Plugging in the given values:
distance = 138.56 m
horizontal velocity = 13.0 m/s
time = 138.56 m / 13.0 m/s
time ≈ 10.66 seconds
Therefore, the frisbee remained aloft for approximately 10.66 seconds.