Posted by Sherri on Sunday, September 9, 2007 at 9:58pm.
A sample of 4 different calculators is randomly selected from a group containing 17 that are defective and 36 that have no defects. What is the probability that at least one of the calculators is defective?

Statistics  Amanda, Monday, September 10, 2007 at 12:03am
17/36

Statistics  MathGuru, Monday, September 10, 2007 at 8:41am
Find P(0), then take 1  P(0) for your probability (since the problem says "what is the probability that at least one" is defective). Using the binomial probability function (you can use a binomial probability table as well):
P(x) = (nCx)(p^x)[q^(nx)]
n = 4
x = 0
p = 17/53 = .32 (note: 53 = 17 + 36)
q = 1  p = .68
Substituting:
P(0) = (4C0)(.32^0)(.68^4) = .2138
Now, take 1  .2138 >this will be your probability.
I hope this helps.
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