Post a New Question

Statistics

posted by .

A sample of 4 different calculators is randomly selected from a group containing 17 that are defective and 36 that have no defects. What is the probability that at least one of the calculators is defective?

  • Statistics -

    17/36

  • Statistics -

    Find P(0), then take 1 - P(0) for your probability (since the problem says "what is the probability that at least one" is defective). Using the binomial probability function (you can use a binomial probability table as well):
    P(x) = (nCx)(p^x)[q^(n-x)]
    n = 4
    x = 0
    p = 17/53 = .32 (note: 53 = 17 + 36)
    q = 1 - p = .68
    Substituting:
    P(0) = (4C0)(.32^0)(.68^4) = .2138
    Now, take 1 - .2138 -->this will be your probability.

    I hope this helps.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question