Posted by **Kristen** on Sunday, September 9, 2007 at 9:44pm.

A hot air balloon is ascending at the rate of 13 m/s and is 75 m above the ground when a package is dropped over the side. How long does the package take to reach the ground? With what speed does it hit the ground?

- physics -
**bobpursley**, Sunday, September 9, 2007 at 10:20pm
Vf^2=Vi^2+ 2gd where g=-9.8 and d=-75

How long?

Vf=Vi+at solve for t (remember Vf will be negative)

- physics -
**drwls**, Sunday, September 9, 2007 at 10:38pm
The height of the package vs. time is

y = 75 + 13 t - 4.9 t^2

Set y=0 and solve for t. Use the quadratic equation and take the solution for which t>0.

For the speed when it hits the ground, use the time t from the first step and

V = 13 - 9.8 t

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