The radius of a lead atom is 175 pm. How many lead atoms would have to be laid side by side to span a distance of 4.20 mm?

wouldn't you divide the 4.20mm by 175pm?

Normally, you need to convert both to meters.

However, technology is on the side of laziness, so paste this in the Google window and press return

4.20mm/175pm

1.6x10^7

To find the number of lead atoms required to span a given distance, we'll first calculate the length of each lead atom.

Given:
Radius of a lead atom = 175 pm

The diameter of an atom is twice its radius. Therefore, the diameter of a lead atom is 2 * 175 pm = 350 pm.

To convert picometers (pm) to millimeters (mm), we divide by 10^6:
350 pm = 350 / 10^6 mm = 0.35 × 10^-3 mm

Now that we know the length of each lead atom, we can calculate the number of atoms required to span a distance of 4.20 mm:

Number of lead atoms = Total distance / Length of each lead atom

Number of lead atoms = 4.20 mm / 0.35 × 10^-3 mm

Now, calculating the above expression:
Number of lead atoms = 12,000 atoms (rounded to the nearest whole number)

Therefore, it would take approximately 12,000 lead atoms laid side by side to span a distance of 4.20 mm.

To find out how many lead atoms would have to be laid side by side to span a distance of 4.20 mm, we need to calculate the length of a single lead atom and then divide the total distance by that length.

Given:
Radius of a lead atom = 175 pm
Distance = 4.20 mm

To calculate the length of a single lead atom, we can use the fact that the radius is half of the diameter:
Diameter of a lead atom = 2 * radius = 2 * 175 pm = 350 pm

To convert the diameter from picometers (pm) to millimeters (mm), we need to divide by 1000:
Diameter of a lead atom = 350 pm / 1000 = 0.35 mm

Now, we can calculate the number of lead atoms laid side by side:
Number of lead atoms = distance / diameter of a lead atom
Number of lead atoms = 4.20 mm / 0.35 mm = 12

Therefore, 12 lead atoms would have to be laid side by side to span a distance of 4.20 mm.