A drowsy cat spots a flowerpot that saild first up and then down past an open window. The pot was in view for a total of .43 s, and then top-to-bottom height of the window is 2m. How high above the window top did the flowerpot go?
Let V2 be the velocity as the pot goes by the bottom of the windowm and V1 be the velocity as it goes by the bottom. The time-averaged velocity as it passes by is (V1 + V2)/2 = 2/0.43 = 4.65 m/s
The change in velocity as it goes by is (V1-V2)/2 = gt = 9.8 m/s^2*0.43 = 0.42 m/s
You now have two equations that let you solve for both V1 and V2
V1 + V2 = 9.30 m/s
V1 - V2 - 0.42 m/s
2 V2 = 8.88 m/s
V2 = 4.44 m/s
The height H above the window that the pot travels can be obtained by setting the kinetic energy at V2 equal to the gain of potential energy at the highest point:
M g H = (1/2) M V2^2
H = V2^2/2g = 1.01 meter
thank you SOOOO much, i spent a long time trying to figure this out
I made a mistake typing one sentence and equation. A "1/2" factor should not have been in the velocity charge equation. It should have read
<<The change in velocity as it goes by is (V1-V2)= gt = 9.8 m/s^2*0.43 = 0.42 m/s>>
It does not affect the answer because I ignored the "/2" when doing the numbers
YOUREWRONG
I don't understand how you get .42 from 9.8*.43
Every time I do this I get 4.2 m/s and I would like to know what I am doing wrong or if you are making a mistake.
To find out how high above the window top the flowerpot went, we can use the information given about the total time the flowerpot was in view and the height of the window.
First, let's break down the problem:
1. The total time the flowerpot was in view is given as 0.43 s.
2. The height of the window is given as 2m.
To find the height above the window top that the flowerpot reached, we can use the concepts of symmetry and free-fall motion. Since the flowerpot was seen first going up and then down past the window, we can assume that it traveled the same distance above the window as it did below the window.
The total distance traveled by the flowerpot is the sum of the distance above the window and the distance below the window. Therefore, each distance is half of the total distance traveled by the flowerpot.
Let's calculate it step by step:
1. Calculate the total distance traveled by the flowerpot:
Total distance = (2 * window height) = (2 * 2m) = 4m
2. Divide the total distance by 2 to get the distance above and below the window:
Distance above window = Total distance / 2 = 4m / 2 = 2m
3. The distance above the window top is the answer we are looking for. Therefore, the flowerpot went 2 meters above the window top.
So, the height above the window top that the flowerpot reached is 2 meters.