Hi: We have a homework problem that I have no idea even how to set up! please help!

"A man jogs at a speed of 1.3 m/s. His dog waits 1.4s then takes off running at a speed of 2.8 m/s to catch the man. How far will they have to travel before the dog watches up with the man? Answerin units of m"

Sure, I'd be happy to help you set up the problem and find the answer!

To solve this problem, we can use the formula:

Distance = Speed × Time

Let's break down the problem and label the information we have:

The man is jogging at a speed of 1.3 m/s.
The dog waits for 1.4 seconds before starting to run.
The dog runs at a speed of 2.8 m/s.

Now, let's determine the time it takes for the dog to catch up with the man.

Since the dog starts running 1.4 seconds after the man, we can calculate the time it takes for the dog to catch up using the formula:

Time = Distance / Speed

The distance traveled by the dog is the same as the distance traveled by the man when the dog catches up. Let's represent this distance as "d."

For the man:
Time = d / 1.3

For the dog:
Time = (d - x) / 2.8

Here, "x" represents the distance the man travels during the time the dog waits (1.4 seconds).

Since both times are equal (the man and the dog take the same amount of time to reach the same point), we can equate the two equations:

d / 1.3 = (d - x) / 2.8

Now, we can solve this equation to find the value of "d" (the distance they have to travel before the dog catches up with the man).

To solve the equation:

1. Multiply both sides of the equation by the common denominator (1.3 × 2.8) to eliminate the denominators.
2.8d = 1.3(d - x)

2. Distribute on the right side of the equation:
2.8d = 1.3d - 1.3x

3. Move all the terms involving "d" to one side and all the terms involving "x" to the other side:
2.8d - 1.3d = -1.3x

4. Combine like terms:
1.5d = -1.3x

5. Now, we need to find the value of "x" to substitute it into the equation. We know that the man runs at a speed of 1.3 m/s for a time of 1.4 seconds, so we can calculate the distance the man travels during this time using the formula: Distance = Speed × Time.
x = 1.3 × 1.4

6. Substitute the value of "x" back into the equation:
1.5d = -1.3(1.3 × 1.4)

7. Solve for "d":
1.5d = -1.3(1.82)
1.5d = -2.366

Divide both sides of the equation by 1.5:
d ≈ -1.58

However, distance cannot be negative in this context, so we discard the negative value.

Therefore, the distance they have to travel before the dog catches up with the man is approximately 1.58 meters.

Please, let me know if I can help you with anything else!