Math
posted by Greg on .
How do you factorise
13x^2+113x22

That polynomial does not factor simply.
The roots of 13x^2+113x22 = 0
are real numbers, since b^2  4 ac = 11625. The expression can be written
13(x A)(xB), where A and B are
A = (113 + sqrt 11625)/26 = 0.19926
and
B = (113  sqrt 11625)/26 = 8.49305
13x^2+113x22 =
= 13(x0.19926)(x8.49305)
= (13x+2.59038)(x8.49305)