Posted by **Greg** on Sunday, September 9, 2007 at 3:01am.

How do you factorise

-13x^2+113x-22

- Math -
**drwls**, Sunday, September 9, 2007 at 8:54am
That polynomial does not factor simply.

The roots of -13x^2+113x-22 = 0

are real numbers, since b^2 - 4 ac = 11625. The expression can be written

-13(x- A)(x-B), where A and B are

A = (-113 + sqrt 11625)/-26 = 0.19926

and

B = (-113 - sqrt 11625)/-26 = 8.49305

-13x^2+113x-22 =

= -13(x-0.19926)(x-8.49305)

= (-13x+2.59038)(x-8.49305)

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