Rubidium has 2 common isotopes, Rb 85 and Rb 87. If the abudance of Rb 85 is 70 percent and the abundance of Rb 87 is 30 percent, what is the average atmoic mass of rubidium?

For the above question, does this mean I would multiple 85 by .70, 87 by .30, and average those two answers? Thank you!

Yes; however the answer you get will not be exact since the atomic masses of isotopes 85 and 87 are not exactly 85 and 87. There are small differences due to binding energy (Relativity effects).

85+87

2

Well i thought to calculate the average atomic mass, you would have to turn the percentages into a decimal and multiply 85 by .70 and 87 by .30 and add them together, there is no need to divide.

58+87

the terms"average atomic mass is............ Average,and

so is calculate different from a "normal" Average?

488.3 repeating

To calculate the average atomic mass of rubidium, you need to multiply the mass of each isotope by its relative abundance and then sum the results. Here's how you can apply it to the given data:

1. Multiply the mass of Rb-85 (85 atomic mass units) by its relative abundance (0.70):
85 amu x 0.70 = 59.5 amu

2. Multiply the mass of Rb-87 (87 atomic mass units) by its relative abundance (0.30):
87 amu x 0.30 = 26.1 amu

3. Add the results from step 1 and step 2 to get the average atomic mass:
59.5 amu + 26.1 amu = 85.6 amu

Therefore, the average atomic mass of rubidium is 85.6 atomic mass units (amu).