limit as x approaches +infinity of (1 + 1/x)^x = e
= x [(1/x) + (1/x)^2 + ...] = 1 + 1/x + (1/x)^2 I used a well known Taylor series for log (1+x) Lim log f(x) as x-> infinity = 1 Therefore the limiti of f(x) is e
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