write equation in standard form.
E(-3,-6) and F(-5,-7)
First, find the slope.
slope= (y2-y1)/(x2-x1)
Second, chose one of your coordinates and plug in...
[y - y1(or y2)]= m[x - x1 (or x2)]
standard form:
For example, 3x + 4y =10 (notice how the x and y are on one side)
m is the slope just so you know
To write the equation of a line in standard form, we need to use the point-slope form of the equation and then rearrange it.
The point-slope form of a linear equation is given by:
(y - y1) = m(x - x1)
Where (x1, y1) represents a point on the line and "m" represents the slope of the line.
To find the slope (m) of the line passing through points E(-3, -6) and F(-5, -7), we use the formula:
m = (y2 - y1) / (x2 - x1)
Substituting the coordinates, we have:
m = (-7 - (-6)) / (-5 - (-3))
= (-7 + 6) / (-5 + 3)
= -1 / -2
= 1/2
So, we have found the slope (m) as 1/2.
Now, we can use the point-slope form with one of the given points, such as E(-3, -6):
(y - (-6)) = (1/2)(x - (-3))
(y + 6) = (1/2)(x + 3)
Next, we simplify the equation:
y + 6 = (1/2)x + 3/2
To eliminate fractions, we can multiply the entire equation by 2:
2(y + 6) = 2(1/2)x + 2(3/2)
2y + 12 = x + 3
Finally, rearranging the equation to the standard form:
x - 2y = -9
Therefore, the equation of the line passing through points E(-3, -6) and F(-5, -7) in standard form is x - 2y = -9.