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March 3, 2015

March 3, 2015

Posted by **Mary** on Tuesday, September 4, 2007 at 10:05pm.

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Physics please clarify - bobpursley, Tuesday, September 4, 2007 at 9:06pm

stop looking for formulas. Voltage is q/distance. It is a scalar, so you add all the contributing charges. In this case,

voltage at empty corner= voltage from each charge

0= q/s -3q/s + x/d

where s is the side distance, and d is the distance from the empty corner to the center. d=.707s.

solve for x.

I am sorry for being such a bother,I appreciate all of the help you've given to me but I am still not getting this one! I think I am over thinking this problem. This is what i did so far please tell me if I am on the right track:

q/s - 3q/s + X/d = 0

-2q/s + X/d = 0

X/d = 2q/s

X= (2q/s)(d)

from here I am stumped.

- Physics please clarify -
**drwls**, Wednesday, September 5, 2007 at 6:05amI answered this once before. You have a geometrical relationship between a and s, d=.707s , so d/s can be converted to a constant. This gives you an equation that relates X to q.

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