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November 28, 2014

November 28, 2014

Posted by **Mary** on Tuesday, September 4, 2007 at 8:58pm.

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A charge of +2q is fixed to one corner of a square, while a charge of -3q is fixed to the diagonally opposite corner. Expressed in terms of q, what charge should be fixed to the center of the square, so the potential is zero at each of the two empty corners?

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Physics - bobpursley, Sunday, September 2, 2007 at 11:10am

Potential is a scalar, so you can just add all four contributions.

Vt= -3q/r + 2q/r + 2X/r=0

solve for charge X

when i use the formula i can up with +1q and the system is saying that the answer is incorrect.

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Physics please clarify - drwls, Monday, September 3, 2007 at 1:17pm

The equation you should be solving is

2q/a -3q/a + (sqrt 2)x/a = 0

Where a is the length of a side of the square. The corners with charges are a distance "a" away from the empty corners, but the center charge x is closer.

Multiplying bith sides by a gives

-q + sqrt 2 * x = 0

x = 0.707 q

Physics please clarify - Mary, Monday, September 3, 2007 at 4:39pm

Can you please explain how you get to x=0.707q.

I got how you got up to -q+sgrt2*X=0 but i keep coming up with a different answer than 0.707q.

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Physics please clarify - bobpursley, Monday, September 3, 2007 at 8:37pm

I misread the problem, thinking you wanted the potential zero at the center, that is why all my distances were the same.

Here, the potential at the two corners is zero. Let s be the side length..so the diagonal length from the corner to the center is s*1/sqrt2

0= -3q/s + +2q/s+ X/(s*1/sqrt2)

then q/sqrt2=X the charge at each corner, or X=.707q at each corner

Physics please clarify - Mary, Monday, September 3, 2007 at 9:34pm

The answer 0.707q is correct but I am still not understanding how to get to that answer.

I have another problem just like this one but with different values for q. When I use the formula above I am coming up with an incorrect answer. Please help. My question is:

A charge of +1q is fixed to one corner of a square, while a charge of -3q is fixed to the diagonally opposite corner. Expressed in terms of q, what charge should be fixed to the center of the square, so the potential is zero at each of the two empty corners?

- Physics please clarify -
**bobpursley**, Tuesday, September 4, 2007 at 9:06pmstop looking for formulas. Voltage is q/distance. It is a scalar, so you add all the contributing charges. In this case,

voltage at empty corner= voltage from each charge

0= q/s -3q/s + x/d

where s is the side distance, and d is the distance from the empty corner to the center. d=.707s.

solve for x.

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