which of the following professonal baseball playershad the best batting average during 1999 season
a. 188 hits in 620 at bat
b.181 in 575 at bat
c. 152 hits in 601 at bat?
i chose b but i am not sure i am right
please help me
To determine each batting average, divide the number of hits (first number) by the number of attempts (second number).
For example "212 hits in 499 at bat," you would divide 212 by 499. (That would be 212/499.) Their batting average would be .4248.
Do that process for a, b, and c, and the highest number (best average) will be the answer.
you are right the correct answer is b
Thank you Michael
Thank you Cyleste
To determine which professional baseball player had the best batting average during the 1999 season, we need to calculate the batting average for each player using the formula:
Batting Average = Number of Hits / Number of At-Bats
Let's calculate the batting averages for each player:
a. For player a, who had 188 hits in 620 at-bats:
Batting Average = 188 / 620
Batting Average ≈ 0.303
b. For player b, who had 181 hits in 575 at-bats:
Batting Average = 181 / 575
Batting Average ≈ 0.3148
c. For player c, who had 152 hits in 601 at-bats:
Batting Average = 152 / 601
Batting Average ≈ 0.253
From the calculations, we can see that player b had the highest batting average, approximately 0.3148. Therefore, your choice of player b having the best batting average during the 1999 season is correct.