if you invest a total of 1000 dollars, part at 6% and part at 8%, if you invest x dollars at 6%, then how much do you invest at 8%?
x dollars invested at 6%.
Then 1000 dollars(total) - x dollars(at 6%) is invested at 8%.
for the x dollar at 6% would that be 1.06x? or wut? thanks..
For the interest at 6%, it is 0.06*x.
The interest on the 8% money is
0.08*(1000-x)
To find out how much you should invest at 8% given that you invest x dollars at 6%, we need to set up an equation based on the total investment amount.
Let's say you invest x dollars at 6%. This means the remaining amount you invest at 8% will be 1000 - x dollars (since the total investment is 1000 dollars).
Now, we can set up the equation based on the interest earned from each investment:
Interest from investment at 6% + Interest from investment at 8% = Total interest earned
The interest earned from the investment at 6% can be calculated as:
(x dollars) * (6/100) = 0.06x dollars
The interest earned from the investment at 8% can be calculated as:
(1000 - x dollars) * (8/100) = 0.08 * (1000 - x) dollars
Now, we can set up the equation:
0.06x + 0.08 * (1000 - x) = Total interest earned
Since we want to find out how much you should invest at 8%, we need to solve this equation for x.
Let's solve it step-by-step:
0.06x + 0.08 * (1000 - x) = Total interest earned
0.06x + 80 - 0.08x = Total interest earned
0.06x - 0.08x = Total interest earned - 80
-0.02x = Total interest earned - 80
x = (Total interest earned - 80) / (-0.02)
Now, without knowing the total interest earned or any specific values, we can't calculate the exact amount you should invest at 8%. We would need more information to solve for x and determine the investment amounts at each interest rate.