Posted by manny on Tuesday, September 4, 2007 at 2:31pm.
Suppose a code consist of two letters followed by a digit. Find the number of
(b) Codes with distinct letters
(c) Codes with the same letters
- math - mathstudent, Tuesday, September 4, 2007 at 4:51pm
Assuming there are 26 letters (no distinction among case) and 10 digits:
A) 26 * 26 * 10 = 6760
B) 26 * 25 * 10 = 6500
C) 26 * 1 * 10 = 260
- math - Anonymous, Sunday, September 9, 2007 at 2:48am
The way of labeling a code with two letters followed by a digit
Assigning one of the 26 letters: A, B, C, D…., F
Assigning one of the 10 digits: 0, 1, 2…, 9
There are two letters so 26
By product rule there are 26×26×10 = 6760 codes
b) Codes with distinct letters
The way the distinct letters are label
25 character of first letters and 25 characters for the second letter so
There are 26×25×10=6500 codes
c) Codes with same letters
The way the same letters are label
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