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Water from a garden hose that is pointed 29° above the horizontal lands directly on a sunbather lying on the ground 4.7 m away in the horizontal direction. If the hose is held 1.4 m above the ground, at what speed does the water leave the nozzle?

  • Physics -

    The time that each drop of water remains in the air is
    t = (4.7 m)/V cos 29 .
    That is based upon how far it travels

    The time t must also satissfy
    1.4 + (V sin 29) t - (g/2) t^2 = 0
    That is based upon the vertical equation of motion.
    Substitute t from the first equation into the second equation and solve for V.

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