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July 25, 2014

July 25, 2014

Posted by **Jim** on Monday, September 3, 2007 at 11:02am.

Two capacitors are identical, except that one is empty and the other is filled with a dielectric ( = 4.20). The empty capacitor is connected to a 18.0 V battery. What must be the potential difference across the plates of the capacitor filled with a dielectric such that it stores the same amount of electrical energy as the empty capacitor?

_________ V

- Physics -
**drwls**, Monday, September 3, 2007 at 3:50pmThe capacitor with the dielectric (#2) will have 4.2 times the C-value of the air-gap capacitor (#1). Let's call the capacitances C1 and C2 = 4.2 C1.

Since the energies (E) are equal,

E1 = (1/2) C1 V^2 = E2 = (1/2) C2 V2^2

C1 * 18^2 = (4.2 C1) * V2^2

V2^2 = (1/4.2) * 324

Solve for V2

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