Homework Help: Physics

Posted by Jim on Monday, September 3, 2007 at 11:01am.

Can please help me understand this question?

A capacitor has a capacitance of 2.0 10-8 F. In the charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 540 V, how many electrons have been transferred?
________electrons

Physics - drwls, Monday, September 3, 2007 at 3:55pm
Compute the charge Q associated the V = 540 V voltage difference using the formula
Q = C V

Then divide Q by the electron charge (1.6*10^-19 C) to get the number of electrons transferred.

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