Homework Help: Physics

Posted by Mary on Monday, September 3, 2007 at 8:20am.

An electric force moves a charge of +1.40 x 10^-4 C from point A to point B and performs 4.70 x 10^-3 J of work on the charge.

(a) What is the difference (EPEA - EPEB) between the electric potential energies of the charge at the two points?
____________J

(b) Determine the potential difference (VA - VB) between the two points.

____________V

(c) State which point is at the higher potential.

_____Point A
_____Point B
_____They are at the same potential.

Physics - drwls, Monday, September 3, 2007 at 8:27am
(a) The electric potential energy decrease, (EPEA - EPEB), equals the work done by the force
(b) Divide (EPEA - EPEB) by the charge to get the electric potential difference
(c) (EPEA - EPEB) is positive, and so is VA - VB. That should tell you which is V higher.

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