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September 16, 2014

September 16, 2014

Posted by **vickel** on Monday, September 3, 2007 at 2:43am.

- maths -
**drwls**, Monday, September 3, 2007 at 5:48amLet x be the number of sons and y be the number of daughters.

x-1 = y = (The number of brothers each son has)

y-1 = x/2 = (The number of sisters each daughter has)

y-1 = (1/2) (y+1)

y/2 = 3/2

y = 3

x = 4

Total number of children = x+y = 7

- maths -
**bgd**, Monday, October 29, 2007 at 8:57ambdg

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