Posted by Corin on .
I need to find the slope of the graph of the function at the given point.
Function:
f(theta)=4sin(theta)(theta)
Point:
(0,0)
I tried finding the derivative of the function at theta=0, but I got 0 for an answer.
I checked the answer in the back of my book and it is 3.
I just need to figure out how to get there.
Thanks to anyone who tries to help me.
Cori

Calculus 
drwls,
The derivative of f(theta) is
f'(theta) = 4 cos(theta) 1
When theta = 0, the value of the derivative is 4 1 = 3. 
Calculus 
Corin,
Only one question: How did you get 1 from theta ?
Thanks so much! 
Calculus 
drwls,
The derivative of f(thetha) = theta is
f'(theta) = df/d(theta) = 1. It's the same thing as saying the derivative of
f(x) = x is f'(x) = 1. 
Calculus 
Corin,
Thanks so much. I get it now.