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August 30, 2014

August 30, 2014

Posted by **Corin** on Monday, September 3, 2007 at 1:42am.

Function:

f(theta)=4sin(theta)-(theta)

Point:

(0,0)

I tried finding the derivative of the function at theta=0, but I got 0 for an answer.

I checked the answer in the back of my book and it is 3.

I just need to figure out how to get there.

Thanks to anyone who tries to help me.

--Cori

- Calculus -
**drwls**, Monday, September 3, 2007 at 2:17amThe derivative of f(theta) is

f'(theta) = 4 cos(theta) -1

When theta = 0, the value of the derivative is 4 -1 = 3.

- Calculus -
**Corin**, Monday, September 3, 2007 at 2:25amOnly one question: How did you get -1 from -theta ?

Thanks so much!

- Calculus -
- Calculus -
**drwls**, Monday, September 3, 2007 at 5:37amThe derivative of f(thetha) = theta is

f'(theta) = df/d(theta) = 1. It's the same thing as saying the derivative of

f(x) = x is f'(x) = 1.

- Calculus -
**Corin**, Monday, September 3, 2007 at 6:36pmThanks so much. I get it now.

- Calculus -

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