sixth squareroot of 27a6b3 + 7a eight squareroot of 81b4? please help me
(27a^6b^3)^(1/6) + 7a(81b^4)^(1/8) ?? then... = [(3^3)(a^6)(b^3)]^(1/6) + 7a[(3^4)(b^4)]^(1/8) =(3^(1/2)(a)(b)^(1/2) + 7a(3^(1/2))(b^(1/2)) = 8a√(3b)
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