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December 20, 2014

December 20, 2014

Posted by **girl** on Sunday, September 2, 2007 at 10:56pm.

sixth squareroot of 27a6b3 + 7a eight squareroot of 81b4?

please help me

- math -
**Reiny**, Sunday, September 2, 2007 at 11:55pmdid you mean

(27a^6b^3)^(1/6) + 7a(81b^4)^(1/8) ??

then...

= [(3^3)(a^6)(b^3)]^(1/6) + 7a[(3^4)(b^4)]^(1/8)

=(3^(1/2)(a)(b)^(1/2) + 7a(3^(1/2))(b^(1/2))

= 8a√(3b)

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