Sunday

April 20, 2014

April 20, 2014

Posted by **~christina~** on Sunday, September 2, 2007 at 1:22am.

For this it's explained in the lab book for physics as if the function is y=mx+b it would be a straight line but if it's y=mx^2+b then it is a parabola. It's explained that to get a straight line I should go and make the equation with the square y=mx'+b with x'= x^2. Then it says that if you plotted these numbers with the corresponding y values you'd get a straight line.

I'm not sure I understand how this would work.

For the 2nd part, wouldn't the slope be the same as the original equation (3)? and the y intercept be the same as the original equation too (4)?

Thanks =D

- graphing -
**drwls**, Sunday, September 2, 2007 at 4:05amLet x = t^2 and use equal increments of t^2 along the x axis, when plotting y vs x.

For t = 0, x = 0.

For t = 1, x = 1.

For t = 1.414, x = 2

For t = 1.732, x = 3 .

For t= 2, x = 4, etc.

The slope of the line you get will be 3.

- graphing -
**~christina~**, Sunday, September 2, 2007 at 10:21amOkay thanks but wouldn't the y intercept still equal 4 DrWls?

- graphing -
**drwls**, Sunday, September 2, 2007 at 5:48pmYes, when you plot y vs x (=t^2) . I forgot to mention the intercept. Sorry

- graphing -
**~christina~**, Sunday, September 2, 2007 at 9:29pmThanks DrWls =D

- graphing -
**G**, Wednesday, September 11, 2013 at 5:33pmI have no idea how to do this

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