An equipotential surface that surrounds a +2.7 x 10^-7 C point charge has a radius of 0.13 m. What is the potential of this surface?
V = k Q/R
k is the Coulomb constant, R = 0.13 m and Q is the charge in Coulombs. The answer will be in volts.
To find the potential of an equipotential surface surrounding a point charge, we can use the formula for the electric potential due to a point charge:
V = k * Q / r
Where:
V is the electric potential
k is the electrostatic constant (approximately equal to 9 x 10^9 N m^2/C^2)
Q is the charge
r is the distance from the point charge to the equipotential surface
In this case, the charge (Q) is given as +2.7 x 10^-7 C, and the radius (r) of the equipotential surface is given as 0.13 m.
Plugging in these values into the formula, we get:
V = (9 x 10^9 N m^2/C^2) * (2.7 x 10^-7 C) / 0.13 m
Now, let's calculate the potential:
V = (9 x 10^9 N m^2/C^2) * (2.7 x 10^-7 C) / 0.13 m
= (2.43 x 10^3 N m^2/C) / 0.13 m
= 1.87 x 10^4 N/C
Therefore, the potential of the equipotential surface surrounding the point charge is 1.87 x 10^4 N/C.