Posted by **Bee** on Saturday, September 1, 2007 at 5:25pm.

Solve the following system of linear inequalities by graphing.

x-3y>6

3x+2y>12

For the first equation I came up with y<1/3x+-2 (I flipped the sign because I divided by a negative)

The second equation, y>-3/2x+6

For the graph: could someone explain in detail what side of the line I graph? Thanks!!!!

- Algebra -
**bobpursley**, Saturday, September 1, 2007 at 6:03pm
Plot those lines (y=1/3x -2, and the othera, making the lines dashes. Your solution is the area which is above the second line, and below the first.

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