Algebra
posted by Bee on .
Solve the following system of linear inequalities by graphing.
x3y>6
3x+2y>12
For the first equation I came up with y<1/3x+2 (I flipped the sign because I divided by a negative)
The second equation, y>3/2x+6
For the graph: could someone explain in detail what side of the line I graph? Thanks!!!!

Plot those lines (y=1/3x 2, and the othera, making the lines dashes. Your solution is the area which is above the second line, and below the first.