Wednesday

October 1, 2014

October 1, 2014

Posted by **sammy** on Saturday, September 1, 2007 at 5:07pm.

1. determine the other x-intercept

2. find an equation for the circle

so i know two points on the circle are (0,3) and (1,0) and the equation for a circle is (x-a)^2 + (y-b)^2 = r^2 but i don't know how to solve the two questions

- calc -
**Count Iblis**, Saturday, September 1, 2007 at 5:53pmThe circle is tangent to the y-axis at y = 3. From this it follows that the center of the circle must be located somewhere on the line y = 3. Therefore b = 3.

The point (0,3) is on the circle, so:

a^2 = r^2

The point (1,0) is on the circle:

(1-a)^2 + 9 = r^2

Suntracting these two equations gives:

a^2 - (1-a)^2 = 0 ---->

(2a - 1) =0---->

a = 1/2

And for this you can easily find r.

**Answer this Question**

**Related Questions**

math - A circle is tangent to the y-axis at y=3 and has one intercept at x=1. a...

math - a circle is tangent to the y-axis at y=3 and has one x-intercept at x=1 a...

Math - A circle is tangent to the y-axis at y=3 and has one x-intercept at x=1, ...

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

maths - 1) Circle centre (7,-2) passes through (-2,10). Calculate radius and ...

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

calc - standard equations of circles that have centers on line 5x-2y=-21 and are...

Math - Find the equation of the circle that passes through the origin and x-...