Posted by Mary on Saturday, September 1, 2007 at 9:42am.
There are two forces acting on the charge at the center.
Due to the -3.2 uC charge at the north point, there is a repulsion force of
F1 = k*(3.0)*(3.2)*10^-12/(0.135)^2
and it points to the south.
Due to the +5.0 uC charge at the east point, there is an attraction force of
F2 = k*(5.0)(3.2)*10^-12/(0.135)^2
and it points to the east.
k is the Coulomb's Law constant,
9.0 x 10^9 N • m2 / C
Do the multiplication and add the two forces vectorially. The direction of the resultant force will be
arctan 5.0/3.0 = 59.0 degrees south of (clockwise from) east, since 5/3 is the ratio of the two component forces.
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