Wednesday

August 27, 2014

August 27, 2014

Posted by **Anonymous** on Friday, August 31, 2007 at 5:40pm.

- calculus -
**Count Iblis**, Friday, August 31, 2007 at 7:36pmThe general equation for a circle is:

(x-a)^2 + (y-b)^2 = R^2

R is the radius of the circle and the point (a,b) is the center. To solve the problem you just insert the coordinates of the three points that are known to be on the circle in the equation and solve for a, b and R:

Origin: x = 0, y = 0:

a^2 + b^2 = R^2

x= 1, y= 0:

(1-a)^2 +b^2 = R^2

x= 0, y= 2:

a^2 + (2-b)^2 = R^2

Subtract from the last two equations the first equation to obtain two equations one containing only a and the other containing only b.

- calculus -
**Anonymous**, Saturday, September 1, 2007 at 5:02pmok so i found:

(y-1)^2 + (x-.5)^2 - r^2

so how do you find r??

**Related Questions**

Math - Find the equation for the following circle: The circle that passes ...

algebra - Find the equation of line making equal and positive intercepts on the ...

Geometry - Within an orthonormal system consider points A(1,4) B(5,1) C(4,8) (a)...

math - Find an equation of the circle that has center (-2, 1) and passes through...

maths - 1) Circle centre (7,-2) passes through (-2,10). Calculate radius and ...

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

math - can u help this the qustion is : A circle passes through the points (1,4...

steev - can u help this the qustion is : A circle passes through the points (1,4...

Math - Find the equation of the circle that satisfies the given conditions. ...

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....