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July 30, 2014

July 30, 2014

Posted by **Anonymous** on Friday, August 31, 2007 at 5:40pm.

- calculus -
**Count Iblis**, Friday, August 31, 2007 at 7:36pmThe general equation for a circle is:

(x-a)^2 + (y-b)^2 = R^2

R is the radius of the circle and the point (a,b) is the center. To solve the problem you just insert the coordinates of the three points that are known to be on the circle in the equation and solve for a, b and R:

Origin: x = 0, y = 0:

a^2 + b^2 = R^2

x= 1, y= 0:

(1-a)^2 +b^2 = R^2

x= 0, y= 2:

a^2 + (2-b)^2 = R^2

Subtract from the last two equations the first equation to obtain two equations one containing only a and the other containing only b.

- calculus -
**Anonymous**, Saturday, September 1, 2007 at 5:02pmok so i found:

(y-1)^2 + (x-.5)^2 - r^2

so how do you find r??

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