I don't really understand this aspect of physics yet, I need help understanding these problems.

Problem One:

Two particles, with identical positive charges and a separation of 2.00 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration a1 whose magnitude is 4.60 103 m/s2, while particle 2 has an acceleration a2 whose magnitude is 8.50 103 m/s2. Particle 1 has a mass of 5.80 10-6 kg.
(a) Find the charge on each particle.
______C
(b) Find the mass of particle 2.
_______kg

Problem Two:

The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q1 = +11.00 µC; the other two have identical magnitudes, but opposite signs: q2 = -5.00 µC and q3 = +5.00 µC.

The drawing has a Y axis and a X axis. Located between the +Y and +X plane are two 45 degree angles with each angle measuring 1.30 meters and 23 degrees.

(a) Determine the net force (magnitude and direction) exerted on q1 by the other two charges.
N ° (measured counter clockwise from the x-axis)
(b) If q1 had a mass of 1.20 g and it were free to move, what would be its acceleration?
m/s2

For Problem One:

(a) To find the charge on each particle, we can use the equation that relates force and acceleration for charged particles: F = qE, where F is the force, q is the charge, and E is the electric field. In this case, since the particles have similar charges, their electric fields cancel each other out, resulting in a net electric field of zero. Therefore, the net force acting on each particle is equal to the product of its charge and its acceleration.

For particle 1, we have F1 = m1 * a1, where F1 is the net force on particle 1, m1 is the mass of particle 1, and a1 is the acceleration of particle 1.

We are given that a1 = 4.60 * 10^3 m/s^2 and m1 = 5.80 * 10^-6 kg. Plugging these values into the equation, we get:

F1 = (5.80 * 10^-6 kg) * (4.60 * 10^3 m/s^2)

Solving this equation will give us the net force acting on particle 1.

Similarly, for particle 2, we have F2 = m2 * a2, where F2 is the net force on particle 2, m2 is the mass of particle 2, and a2 is the acceleration of particle 2.

We are given that a2 = 8.50 * 10^3 m/s^2. We need to find the mass of particle 2, so we can express F2 in terms of m2.

Once we have the net forces on each particle, we can equate them, since they are equal in magnitude (but opposite in direction) due to Newton's third law of motion involving charged particles. This equation will allow us to solve for the charges on the particles.

(b) To find the mass of particle 2, we can rearrange the equation F2 = m2 * a2 and solve for m2. We already know the net force on particle 2 (F2) and its acceleration (a2).

Solving this equation will give us the mass of particle 2.

For Problem Two:

(a) To find the net force exerted on q1 by the other two charges, we need to calculate the forces exerted by q2 and q3 individually, and then find their resultant.

The force between two charges q1 and q2 can be calculated using Coulomb's Law:

F12 = k * |q1| * |q2| / r12^2

where F12 is the force exerted by q2 on q1, k is Coulomb's constant, |q1| and |q2| are the magnitudes of the charges, and r12 is the distance between the charges.

Similarly, we can calculate the force between q1 and q3 using the same equation.

After calculating the forces individually, we can find their resultant force by adding them as vectors. This will give us the magnitude and direction (angle) of the net force exerted on q1 by the other two charges.

(b) To find the acceleration of q1 if it were free to move, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass:

a = F / m

Here, we already have the net force acting on q1 (from part a) and its mass, which is given as 1.20 g. We just need to convert the mass to kilograms before substituting into the equation.

Solving this equation will give us the acceleration of q1.

1. Get the charge by first computing the accelerating force on particle 1

F = M1 * a1
The force on particle 2 is the same as the force on particle 1, but they don't tell you the mass of M2.
Once you know F, used Coulomb's Law to compute the charge Q on either particle.
F = k Q^2/R^2
You can compute M2 from the relationship
F = M1 a1 = M2 a2.
M2 = (a1/a2) M1

I do not understand your description of Problem 2:
"Located between the +Y and +X plane are two 45 degree angles with each angle measuring 1.30 meters and 23 degrees."
Angles are not measured in meters AND degrees.