Posted by Jim on Thursday, August 30, 2007 at 9:46pm.
Can you please provide me a starting point for these two questions
Three charges are located on the +x axis as follows: q1 = +26 µC at x = 0 m, q2 = +13 µC at x = +2.0 m, and q3 = +42 µC at x = +3.5 m.
(a) Find the electrostatic force (magnitude and direction) acting on q2.
(b) Suppose q2 were -13 µC, rather than +13 µC. Without performing any further detailed calculations, specify the magnitude and direction of the force exerted on q2.
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?
- Physics - bobpursley, Thursday, August 30, 2007 at 10:20pm
1b. q2 being negative, it will be attracted to the left and right, but on the right, the charge is bigger, and closer. Q2 is attracted to the right.
1a. Find the two repulsive forces (F12, F23) and add them as vectors. They are in the opposite direction.
2. If it is attractive, q2 is a negative charge. Use coulombs equation f =k q2q1/r^2 to find q2
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