Can you please provide me a starting point for these two questions
Question One:
Three charges are located on the +x axis as follows: q1 = +26 µC at x = 0 m, q2 = +13 µC at x = +2.0 m, and q3 = +42 µC at x = +3.5 m.
(a) Find the electrostatic force (magnitude and direction) acting on q2.
_______ N
+x
-x
+y
-y
(b) Suppose q2 were -13 µC, rather than +13 µC. Without performing any further detailed calculations, specify the magnitude and direction of the force exerted on q2.
_______ N
-y
-x
+y
+x
Question Two:
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?
______ C
1b. q2 being negative, it will be attracted to the left and right, but on the right, the charge is bigger, and closer. Q2 is attracted to the right.
Force=kq2(q3/1.5^2 -q1/2^2)
1a. Find the two repulsive forces (F12, F23) and add them as vectors. They are in the opposite direction.
2. If it is attractive, q2 is a negative charge. Use coulombs equation f =k q2q1/r^2 to find q2
Here are the starting points for the two questions:
Question One:
(a) To find the electrostatic force acting on q2, we can use Coulomb's Law:
F = k * |q1| * |q2| / r^2
In this case, q1 = +26 µC, q2 = +13 µC, and they are separated by a distance of 2.0 m. We also need the value of the electrostatic constant, k.
(b) For the second part, we are asked to determine the magnitude and direction of the force exerted on q2 if its charge is changed to -13 µC. We can use Coulomb's Law again, but this time, we use the new charge value for q2.
Question Two:
To find the value and sign of q2:
We know that q1 = +3.5 µC, the distance between the particles is 0.25 m, and the force experienced by particle 1 is 2.3 N. We can use Coulomb's Law to solve for q2.
Question One:
To find the electrostatic force acting on q2, we can use Coulomb's law, which states that the electrostatic force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The formula can be written as:
F = k * (|q1| * |q2|) / r^2
where F is the force, k is the electrostatic constant (9.0 x 10^9 Nm^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.
(a) To calculate the force acting on q2, we'll use the formula above with the given values.
|q1| = +26 µC (charge of q1)
|q2| = +13 µC (charge of q2)
r = +(2.0 m - 0 m) = 2.0 m (distance between q1 and q2)
Plugging these values into the formula:
F = (9.0 x 10^9 Nm^2/C^2) * ((26 x 10^-6 C) * (13 x 10^-6 C)) / (2.0 m)^2
Calculating this expression will give you the magnitude of the force acting on q2 in Newtons.
To determine the direction of the force, we can use the principle that like charges repel and opposite charges attract. Since q2 is positive, and q1 is also positive, they will repel each other. Thus, the force acts in the direction opposite to the line joining the two charges. This can be denoted as -x direction.
(b) If q2 were -13 µC instead of +13 µC, the magnitude of the force would remain the same because Coulomb's law only depends on the magnitudes of the charges. However, the direction of the force will change because q2 is now negative. As like charges repel, the force will act in the +x direction. So, the magnitude of the force would still be _______ N, but the direction would be +x.
Question Two:
To find the magnitude and sign of q2, we can rearrange Coulomb's law formula as follows:
F = k * (|q1| * |q2|) / r^2
Solving for |q2|:
|q2| = (F * r^2) / (k * |q1|)
Given values:
|q1| = +3.5 µC (charge of particle 1)
F = 2.3 N (force on particle 1)
r = 0.25 m (distance between the particles)
Plugging these values into the formula:
|q2| = (2.3 N * (0.25 m)^2) / ((9.0 x 10^9 Nm^2/C^2) * (3.5 x 10^-6 C))
Calculating this expression will give you the magnitude of q2 in Coulombs. The sign of q2 can be determined from the attractive force experienced by particle 1. Since particle 1 experiences an attractive force, q2 must have an opposite sign to q1, which means it is negative. The final answer for q2 would be ______ C with a negative sign.