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September 2, 2014

September 2, 2014

Posted by **Wendy** on Thursday, August 30, 2007 at 6:51pm.

Age 24+X(a-2) Age human years

2

3

4

5

6

- Math -
**Wendy**, Thursday, August 30, 2007 at 6:56pmI do not understand this math problem at all. It is actually my son's, who is in 7th grade, and the teacher did not explain anything either. If someone could just explain how to figure this out, that would be great.

- Math -
**Ms. Sue**, Thursday, August 30, 2007 at 7:05pmAge 2 = 24 years

Age 3 = 24 years + 4 years = 28 years

Age 4 = 28 years + 4 years = 32 years

And so on --

- Math -
**Wendy**, Thursday, August 30, 2007 at 7:22pmI have not done Alegbra in 30 years so I am quite rusty with it. It just did not occur to me to change the 24 to 28 and so on. Does that mean that X equals (a-2), which would be 4, and that a would be 6?

- Math -
**DrBob222**, Thursday, August 30, 2007 at 7:24pmWith no definitions, it is difficult to know exactly what the teacher wanted but here is the best I can do. It is actually only a little more detailed explanation than the one given by Ms Sue and it takes into accout the factor of 4 years aging + the current age of the cat or dog.

Apparently, the teacher wants a to be the age of the cat or dog and X to be the constant of 4 years. At least that is my take on the problem.

The equation provided is

24 + X(a-2).

a = the age of cat or dog; i.e., 2, 3, 4, 5, 6, etc. in the equation.

X = 4 in the equation.

24 + 4(2-2) = 24+4(0)= 24+0=24

24 + 4(3-2) = 24+4(1)= 24+4=28

24 + 4(4-2) = 24+4(2)= 24+8=32

24 + 4(5-2) = 24+4(3)= 24+12=36

etc.

- Math -
**Wendy**, Thursday, August 30, 2007 at 7:26pmThank you!

- Math -
- Math -
**Rebecca**, Wednesday, August 22, 2012 at 4:20pmThank you for having this online! My kid came home with this problem today. I have a Masters degree, but was still stumped! Time for some refresher courses...

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