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September 16, 2014

September 16, 2014

Posted by **beth** on Thursday, August 30, 2007 at 1:13pm.

- calculus-rate problem -
**bobpursley**, Thursday, August 30, 2007 at 2:06pmLet h be the depth.

Then the base radius (at the top) at depth h is 5*h/12. So volume of water is

V= 1/3 PI (5h/12)^2 h

take the derivative, set it equal to 10, solve for dh/dt when h=8

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