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September 20, 2014

September 20, 2014

Posted by **Michael** on Wednesday, August 29, 2007 at 8:47pm.

When a mass of 5 kilograms is tied to the middle of the clothesline, it sags a distance of 2 meters.

What is the magnitude of the tension on the ends of the clothesline?

Alright, so i have this a little bit started but not sure if I'm going in the right direction. Here's what i have:

sin 2/sqrt(104)

cos 10/sqrt(104)

T1 = -|T1| cos 10/sqrt(104)i + |T1|sin 2/sqrt(104)j

T2 = |T2| cos 10/sqrt(104)i + |T2|sin 2/sqrt(104)j

T1 + T2 + F = 0

Force: -5(9.8)

Do i have this set up right? And if i do, why are certain things positive and negative? What's the next step?

- Vectors/Tension -
**Bobpursley**, Wednesday, August 29, 2007 at 9:04pmThe problem is much simpler than you are doing. Due to symettry, each side is supporting half the weight (1/2 mg= 2.5g)

Now, using your angles

SinTheta=2.5g/Tension

Now substitute for sintheta, 2/sqrt(104) and solve for tension

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