Wednesday

April 16, 2014

April 16, 2014

Posted by **Keema** on Wednesday, August 29, 2007 at 7:00pm.

- Math -
**DrBob222**, Wednesday, August 29, 2007 at 7:13pmI assume the problem is

(3y^2) - (12y/y^3) =

Then you handle the second term:

-12y/9y^3 =

divide 12 and 9 by 3 to give

-4y/3y^3

then divide y in the numerator into y^3 in the denominator to give

-4/3y^2.

You may want to move the 3y^2 out from the denominator; if so, just multiply the entire equation by 3y^2.

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