Wednesday

August 27, 2014

August 27, 2014

Posted by **wendy** on Wednesday, August 29, 2007 at 6:55pm.

f(t)= (1-t)^(1/2)

- calculus -
**~christina~**, Wednesday, August 29, 2007 at 7:25pmf(t)= (1-t)^(1/2)

chain rule

f'(t)= 1/2(x)^(-1/2)dx

x= 1-t

dx= -1

f'(t)= 1/2(1-t)^(-1/2)(-1)

f'(t)= (-1/2)(1-t)^(-1/2)

f'(t)= -1/(2sqrt1-t)

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