Question

find the first derivative of

f(t)= (1-t)^(1/2)

Answer 1

f(t)= (1-t)^(1/2)

chain rule

f'(t)= 1/2(x)^(-1/2)dx

x= 1-t
dx= -1

f'(t)= 1/2(1-t)^(-1/2)(-1)

f'(t)= (-1/2)(1-t)^(-1/2)

f'(t)= -1/(2sqrt1-t)