Posted by wendy on .
find the first derivative of
f(t)= (1t)^(1/2)

calculus 
~christina~,
f(t)= (1t)^(1/2)
chain rule
f'(t)= 1/2(x)^(1/2)dx
x= 1t
dx= 1
f'(t)= 1/2(1t)^(1/2)(1)
f'(t)= (1/2)(1t)^(1/2)
f'(t)= 1/(2sqrt1t)