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calculus

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find the first derivative of
f(t)= (1-t)^(1/2)

  • calculus -

    f(t)= (1-t)^(1/2)

    chain rule

    f'(t)= 1/2(x)^(-1/2)dx

    x= 1-t
    dx= -1

    f'(t)= 1/2(1-t)^(-1/2)(-1)

    f'(t)= (-1/2)(1-t)^(-1/2)

    f'(t)= -1/(2sqrt1-t)

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