Friday

August 28, 2015
Posted by **statstudent** on Wednesday, August 29, 2007 at 12:15pm.

SST = SSM + SSE

MEAN = ∑(X)/N

SST = ∑((x - MEAN)^2)

= ∑(x^2 - 2 * x1 * MEAN + MEAN^2)

= ∑(x^2) - 2 * MEAN * ∑(x) + N * MEAN^2

= ∑(x^2) - 2 * ∑(x)^2/N + ∑(x)^2/N

= ∑(x^2) - ∑(x)^2/N

SSM = ∑((MODEL - MEAN)^2)

= ∑(MODEL^2 - 2 * MODEL * MEAN + MEAN^2)

= ∑(MODEL^2) - 2 * MEAN * ∑(MODEL) + N * MEAN^2

= ∑(MODEL^2) - 2 * MEAN * ∑(MODEL) + N * MEAN^2

= ∑(MODEL^2) - 2/N * ∑(x) * ∑(MODEL) + ∑(x)^2/N

SSE = ∑((x - MODEL)^2)

= ∑(x^2 - 2 * x * MODEL + MODEL^2)

= ∑(x^2) - 2 * ∑(x * MODEL) + ∑(MODEL^2)

SST = SSM + SSE

∑(x^2) - ∑(x)^2/N = ∑(MODEL^2) - 2/N * ∑(x) * ∑(MODEL) + ∑(x)^2/N + ∑(x^2) - 2 * ∑(x * MODEL) + ∑(MODEL^2)

2 * ∑(MODEL^2) - 2/N * ∑(x) * ∑(MODEL) + 2 * ∑(x)^2/N + - 2 * ∑(x * MODEL) = 0

∑(MODEL^2) - 1/N * ∑(x) * ∑(MODEL) + ∑(x)^2/N + - ∑(x * MODEL) = 0

I can't complete the proof. What am I missing? Thanks!

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**Count Iblis**, Wednesday, August 29, 2007 at 1:21pmDivide the sum of squares by N and work with the averages. Let's use the notation:

<X> for the average of X. E.g.:

<X> = ∑(X)/N = Mean

And:

<(X-<X>)^2> =

<X^2 - 2X<X> + <X>^2> =

<X^2> - <X>^2

Note that <a X> = a <X> for a constant factor a. In an average like <X <X>>, the inner <X> is a constant when carrying out the outer average, so you can take it out of the outer average sign. So, you have <X <X>> = <X>^2. The average of a constant is, of course, the same constant so e.g. <<X>^2> = <X^2> because once the inner average is carried out it is a constant w.r.t. the outer average.

If you work with averages and use these rules then you can derive the desired result in just one line. If you use summations, you'll tend to re-derive these rules in every step you make, so you'll get a complicated mess.

Derivation:

<(X - <X>)^2> =

<(X - m + m - <X>)^2> =

<(X-m)^2> + <(m - <X>)^2>

+ 2 <X-m><m-<X>>

The last term is zero if the average of X equals the average of the Model.

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**statstudent**, Wednesday, August 29, 2007 at 3:31pmI don't follow this:

<<X>^2> = <X^2>

Of course, if k is constant and x is variable:

<kx> = k<x>

<k> = k

<k^2> = k^2

but...

<x^2> != <x>^2

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**Count Iblis**, Wednesday, August 29, 2007 at 4:06pmSorry, that was a typo.

I meant to write:

<<X>^2> = <X>^2

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**statstudent**, Wednesday, August 29, 2007 at 5:11pmI don't follow this at all:

<(X - m + m - <X>)^2> = <(X-m)^2> + <(m - <X>)^2> + 2 <X-m><m-<X>>

Trying to follow your logic, for the left side:

<(X - m + m - <X>)^2>

= <(X - <X>)^2>

= <x^2> - <x>^2

= SST

For SSM + SSE:

<(x - m>^2> + <(m - <x>)^2>

= <x^2 - 2xm + m^2> + <m^2 - 2m<x> + <x>^2>

= <x^2> - 2<xm> + <m^2> + <m^2> - 2<m><x> + <x>^2>

= 2<x^2> + 2<m^2> - 2<xm> - 2<m><x>

And I'm stuck...