Posted by Chase on Tuesday, August 28, 2007 at 1:08pm.
It seems to me you could do the following:
PV=nRT
PV = (grams/molar mass)RT
P= gRT/molar mass*V
P*molar mass = (g/v)RT
molar mass = density*RT/P
I plugged in the numbers and obtained about 45 something. Check my thinking. Check my arithmetic.
So the 45 something molar mass is made up of some percentage (or fraction) of 83.80 Kr (check that number) and some percentage (fraction) of 32.00 oxygen. Let x = fraction of oxygen, then 1-x = fraction of Kr.
32.00(x) + 83.80(1-x) = 45 something.
Solve for x. You can convert to grams and to mols and to mol fractions and mol percent from there. I kept looking for a way to obtain partial pressure of oxygen and Kr and from there the mol percent but that didn't happen. I think there may be an easier way to do this but I think the above will get it. Let me know.
Related Questions
chemistry - A 10 liter flask at 298 K contains a gaseous mixture of O2 and CO2 ...
chemistry urgent - a mixture of NO, CO2, and O2 gases has a total pressure of 2....
Chemistry - Consider the reaction below. 3 O2(g) --> 2 O3(g) At 175°C...
Chemistry - Consider the reaction below. 3 O2(g) --> 2 O3(g) At 175°C...
Chemsitry II - The partial pressure of CH4(g) is 0.185 atm and that of O2(g) is ...
chemistry - The air exhaled by an average human being might have the following ...
Chemistry - A solution contains a mixture of pentane and hexane at room ...
ap chemistry - methanol and ethanol are common organic solvents. if the mole ...
CHEMISTRY - A mixture of Xe, Kr, and Ar has a total pressure of 6.7 atm. What is...
College Chemistry - 2NO(g)+O2(g)<->2NO2(g) has KP = 2.77 × ...
For Further Reading
