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April 16, 2014

April 16, 2014

Posted by **Mack** on Monday, August 27, 2007 at 9:48pm.

Employee x is paid $12.50 an hour for the first 36 hours he works in a week, and is paid double that rate for every hour over that. Employee Y is paid $15.00 an hour for the first 40 hours she works in a week, and is paid 1.5 times that rate for every hour over that. On a certain week, both employees worked the same # of hours and were paid the same amount. How many hours did each employee work that week?

The book says I have to Backsolve. What does Backsolve mean? How do I solve this problem?????

- S.A.T Math -
**brie**, Monday, August 27, 2007 at 9:51pmyou work backwards. multiply 12.50 and 36=hours worked in 1 week. do same w/ 15 and 40. keep adding on hours to each employee- make sure to pay them either double or 1.5x more like it says. keep doing this until you come to an equal # of hours for both workers.

- S.A.T Math -
**gabriela**, Monday, August 27, 2007 at 10:02pmIt is like u are a owner of a store... when tony(x) starts you pay him $12.50 an hour for his first day & a half(36 hours) in every week & after that he gets paid $25.00 per hour...

Elanie(y) gets paid $15.00 an hour for the first 40 hours she works for a week & after that she is paid $23.50 for every hour she works after that.

now just make a chart of something that shows how much money they each make per week if they work X amount of hours & stop when they make the same amount working the same amount of hours that week...

HINT : THAT WILL BE A HIGH #....

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**Mack**, Monday, August 27, 2007 at 10:06pmI still don't get it.

- S.A.T Math -
- S.A.T Math -
**gabriela**, Monday, August 27, 2007 at 10:03pmOR U CAN DO WAT BRIE SAID I TEND 2 TAKE THE LONG BUT SAFE WAY...LOLSZ...

- S.A.T Math -
**Mack**, Monday, August 27, 2007 at 10:21pmI don't understand her either.

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**gabriela**, Monday, August 27, 2007 at 10:12pmwhat dont u understand so i can explain it more??

- S.A.T Math -
**DrBob222**, Monday, August 27, 2007 at 10:24pmYou can calculate the amount x gets paid for a 40 hour week.

That will be (36 hours*12.50/hour) + (4 hours*25/hour) = 450 + 100 = $550 for the 40 hour week.

y gets paid for the 40 hours a sum of 40 hours*15/hour = $600 for the 40 hour week.

The problem states that x and y worked the same number of hours and were paid the same. So let H = hours worked (over 40) and set the pay equal to each other like so.

x is paid 550+(25*H)

y is paid 600+(22.5*H). But since they are paid the same we can set them equal.

550+(25H)=600+(22.5H)

Solve for H, the number of hours each worked over the 40 hour week.

I get H = 20 hours so they must have worked 60 hours.

- S.A.T Math -
**gabriela**, Monday, August 27, 2007 at 10:28pmyeah i guess that works to...lolsz

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