a 10 inch flanged cast- iron spool connects two 90 degree elbows. the elbow center lines are separated by a distance of 6 feet. each joint incorporates a 5/16 inch gasket. what would be the length of the spools face to face dimension?
Is this stump the teacher? There are standard distances for flanged elbows measured from center line, and in fact, the distances vary by type of elbow and thickness (pressure rating). Of course, you know that.
ok
my friend gave me this question
i guess i got stumped
I can't seem to get my times enymore
To find the length of the spool's face to face dimension, we need to consider the lengths of the two 90-degree elbows and the distance between their center lines.
Given:
- Flanged cast-iron spool connects two 90-degree elbows.
- Elbow center lines are separated by a distance of 6 feet.
- Each joint incorporates a 5/16 inch gasket.
We need to calculate the length of the spool's face to face dimension.
Here's the step-by-step explanation of how to find the length:
1. Start by finding the length of each 90-degree elbow.
- The length of a 90-degree elbow can vary based on the specific design and manufacturer.
- You can refer to the product specifications or standards to obtain the length of a standard 90-degree elbow.
- Let's assume each elbow has a standard length of 2 feet.
2. Add the lengths of the two elbows:
- Since there are two elbows, each with a length of 2 feet, the total length of the elbows would be 2 feet + 2 feet = 4 feet.
3. Add the distance between the center lines of the elbows:
- The given distance between the center lines of the elbows is 6 feet.
4. Consider the gasket thickness:
- Each joint incorporates a 5/16 inch gasket.
- To include the effect of the two gaskets, we need to add their thickness to the total length calculated in step 2 and step 3.
- Since there are two joints, each with a gasket thickness of 5/16 inch, the total gasket thickness would be 5/16 inch + 5/16 inch = 10/16 inch.
5. Convert the gasket thickness to feet:
- To ensure consistency, we need to convert the gasket thickness from inches to feet.
- Since 12 inches = 1 foot, 10/16 inch is equivalent to (10/16)/12 feet = 10/192 feet = 0.0521 feet (approximately).
6. Add the lengths of the elbows, distance between center lines, and the gasket thickness:
- Total length = Length of elbows + Distance between center lines + Total gasket thickness
- Total length = 4 feet + 6 feet + 0.0521 feet = 10.0521 feet.
Therefore, the length of the spool's face to face dimension would be approximately 10.0521 feet.