Posted by **Joel** on Friday, August 24, 2007 at 6:41pm.

Gabe lives fifteen miles from school and the bus stops seven times at three minutes each between his house and school. The bus arrives at his house at 7:30. Gabe's friend Aaron lives 8 miles from school and the bus stops four times at 2 minutes each between his house and school. The bus arrives at his house at 8:00. What time does each boy arrive at school?

Can someone please help? I have no idea how to turn this into an equation; it seems so long and confusing.

- Algebra -
**bobpursley**, Friday, August 24, 2007 at 7:12pm
|TimeGabe= leaving time + stopping time

Time Aaron= leaving time + stopping time.

- Algebra -
**Joel**, Friday, August 24, 2007 at 10:33pm
I still don't get it! My brain is burnt right now.

- Algebra -
**brie**, Friday, August 24, 2007 at 10:42pm
TimeGabe=leaving time + stopping time

7:51=7:30 + 21(7x3)

Gabe arrives @ 7:51, right?

Then for Aaron:

Time Aaron=leaving time + stopping time

same thing:

8:08=8:00 + 8(4x2)

So Aaron gets there @ 8:08.

- Algebra -
**Joel**, Sunday, August 26, 2007 at 2:51pm
Thank you so much! :)

- Algebra -
**brie**, Sunday, August 26, 2007 at 4:03pm
No problem!

=)brie

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